Another way of doing this is to consider that ##d(secx) = secxtanx*dx##
That is, the derivative of ##secx## is ##secxtanx##
##=> int(secxtanx)/(secx – 1)dx = int d(secx)/(secx – 1)##
This is the same as letting ##u = secx##
We then have,
##int(du)/(u – 1) = ln(u – 1) + C = ln(secx – 1) + C##
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Get The Answer How do you find integral of ##((secxtanx)/(secx-1))dx##?
Another way of doing this is to consider that ##d(secx) = secxtanx*dx##
That is, the derivative of ##secx## is ##secxtanx##
##=> int(secxtanx)/(secx – 1)dx = int d(secx)/(secx – 1)##
This is the same as letting ##u = secx##
We then have,
##int(du)/(u – 1) = ln(u – 1) + C = ln(secx – 1) + C##
Previous answers to this question
This is a preview of an assignment submitted on our website by a student. If you need help with this question or any assignment help, click on the order button below and get started. We guarantee authentic, quality, 100% plagiarism free work or your money back.
Get The Answer