MATH533 Applied Managerial Statistics Final Exam Study Guide
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- When you are finished with the Final Exam, click on the Submit for Grading button.
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- Exam Questions
- There are 10 randomly selected short answer questions each worth varying points, for a total of 250 points.
- The Final Exam covers all course TCOs and Weeks 1–7.
- The Final Exam consists of 3 pages, which can be completed in any order. You may go back and forth between the pages.
- The Final Exam questions are pooled. This means that not everyone will have the same questions. Even if you do have some of the same questions, they may not be in the same order. These questions are distributed among the TCOs. The entire exam is worth 250 points.
- Some of the key study areas are shown below. Although these are key areas, remember that the exam is comprehensive for all of the assigned course content and this study guide may not be all-inclusive.
- TCO A
- Descriptive Statistics and Exploratory Data Analysis
- Central Tendency
- Dispersion
- The Shape of the Distribution
- Numbers, Graphs, and Tables
- One Variable and Two Variables
- TCO B
- Contingency Tables
- The Binomial Distribution
- The Normal Distribution
- TCO C
- Confidence Intervals/Sample Sizes: For the Population Mean
- Confidence Intervals/Sample Sizes: For the Population Proportion
- TCO D
- Hypothesis Tests: For the Population Proportion
- Hypothesis Tests: For the Population Mean
- TCO E
- Simple Linear Regression
- Multiple Regression
- TCO F
- Use of Minitab in each of the above TCOs
- Areas that were discussed in the Discussion areas will be prime targets.
- Homework Assignments and Quizzes will also be prime targets for revisiting.
- Reviewing the TCOs, which are listed below for your convenience, will also be a great preparation for the Final Exam.
| A | Given a managerial problem and accompanying data set, construct graphs (following principles of ethical data presentation), calculate and interpret numerical summaries appropriate for the situation. Use the graphs and numerical summaries as aids in determining a course of action relative to the problem at hand. |
| B | Given a managerial problem, utilize basic probability concepts, and standard probability distributions, e.g., binomial, normal, as is appropriate, to formulate a course of action which addresses the problem. |
| C | Given a managerial problem and accompanying data set, for which application of a confidence interval is appropriate, construct an interval, assess its validity, and use the confidence interval in developing a course of action relative to a problem. |
| D | Given a managerial problem and accompanying data set, for which the test of an hypothesis is appropriate, conduct an appropriate statistical test, assess the validity of the test, and use the test results to decide on a course of action relative to a problem. |
| E | Given a managerial problem and accompanying data set, for which regression analysis—simple or multiple—is appropriate, fit a regression model to the data, determine the validity and utility of the model, and use the model, if appropriate, to determine a course of action intended to deal with a problem. |
| F | Students should be able to perform the necessary calculations for objectives A through E using technology, whether that is a computer statistical package or the TI-83, and be able to use the output to address a problem at hand. |
The following Table provides an overview of the content of the 10 Questions on the Final Exam and the possible points for each Question.
| # | Content | TCO | Points | Minitab and Calculator | Notes |
| 1 | Descriptive Statistics | A | 33 | Minitab Required | |
| 2 | Contingency Table | B | 18 | Calculator Only | |
| 3 | Binomial Distribution | B | 18 | Minitab Required | |
| 4 | Normal Distribution | B | 18 | Minitab Required | |
| 5 | Mean: Confidence
Interval/Sample Size |
C | 18 | Minitab Required
And Calculator |
|
| 6 | Proportion: Confidence
Interval/Sample Size |
C | 18 | Minitab Required
And Calculator |
|
| 7 | Proportion: Hypothesis
Test |
D | 24 | Minitab Required | |
| 8 | Mean: Hypothesis
Test |
D | 24 | Minitab Required | |
| 9 | Simple Linear
Regression |
E | 48 | Minitab Output
Provided |
|
| 10 | Multiple Regression | E | 31 | Minitab Output
Provided |
What follows is a Demo Final Exam with 10 representative problems. Actual problems will be similar, but will vary in the scenario presented, the numbers used, and the particular variation of the problem type presented.
MATH533 Sample Final Exam Demo
Question 1:
TCO A and F
The following raw data is the result of selecting a random sample of new Ford Escorts and testing these cars for fuel efficiency (results are in miles per gallon):
| 40.2 | 32.9 | 29.2 | 26.5 | 33.3 | 28.4 |
| 28.8 | 34.2 | 30.3 | 35.7 | 25.8 | 37.5 |
| 35.6 | 40.8 | 33.3 | 26.6 | 33.5 | 28.1 |
Use Minitab to run the key Descriptive Statistics, i.e., mean, median, mode, standard deviation, variance, quartiles, interquartile range, and range. Interpret your Minitab output, including selected measures of central tendency, dispersion, and the shape of the distribution.
Answer:
Descriptive Statistics: CarsFuel
Total
Variable Count Mean StDev Variance Minimum Q1 Median Q3 Maximum
CarsFuel 18 32.26 4.59 21.10 25.80 28.32 33.10 35.63 40.80
N for
Variable Range IQR Mode Mode
CarsFuel 15.00 7.30 33.3 2
Note: The Final Exam Question may ask for only a selection of the Descriptive Statistics, along with their Interpretation.
Question 2:
TCO B
The following table gives the number of claims at a large insurance company by kind and geographical region.
| East | South | Midwest | West | Totals | |
| Hospitalization | 55 | 328 | 29 | 52 | 464 |
| Physician’s Visit | 233 | 514 | 204 | 251 | 1202 |
| Outpatient Treatment | 100 | 526 | 65 | 102 | 793 |
| Totals | 388 | 1368 | 298 | 405 | 2459 |
- If a bill is chosen at random, what is the probability that it is either from the East or from the West?
- If a bill is chosen at random, what is the probability that it is not for Hospitalization and from the South.
- Given that the bill is from the Midwest, what is the probability that it is for a Physician’s Visit?
- Given that the bill is not from either the East or the West, what is the probability that it is not for a Physician’s Visit?
Answers:
- (# East + #West)/Total = (388 + 405)/2459 = 0.32249
- # Not Hospitalization and Not South/Total = 2131/2459 = 0.866612
- (#from Midwest AND Physician’s Visit)/# from Midwest = 204/298 = 0.68456
- #Not Physician’s Visit/Given #Not from East or West = 948/1666 = 0.56903
Question 3:
TCO B and F
The probability of obtaining a home equity loan from United Bank is 0.40. A random sample of 10 loan applications is selected. Use Minitab to find the following probabilities.
- Find the probability that at least five will get a loan.
- Find the probability that none will get a loan.
- Find the probability that less than three will get a loan.
- Find the probability that three or less, or more than seven will get a loan.
Answers:
- P(X>or =5) = 0.3669
- P(X=0) = 0.006
- P(X<3) = P(X<or=2) = 0.1673
- P(X<or =3) or P(X>or = 8) = 0.38230 + 0.01229 = 0.39459
Question 4:
TCO B and F
The length of time to do a complete full battery check and replacement (if needed) at Insta-Bat is normally distributed with a mean of 16.2 minutes and a standard deviation of 2.4 minutes. Use Minitab to find the required probabilities.
- Determine what percentage of complete full battery check and replacements (if needed) will fall between 10 and 20 minutes.
- What percentage of complete full battery check and replacements (if needed) will take less than 20 minutes?
- Using your answer from B., If 1000 cars had a complete full battery check and replacement (if needed), how many would you expect to be finished in less than 20 minutes?
- What percentage would take less than 10 minutes?
- Management wants to offer customers a guarantee that a complete full battery check and replacement (if needed) can be completed within a certain amount of time. What number of minutes should they include in their guarantee, to be sure they are achieving their goal 99% of the time?
- What number of minutes should they include in their guarantee, to be sure they are achieving their goal 95% of the time?
Answers:
- P(10<X<20) = 0.9384
- P(X<20) = 0.9433
- For 1,000 cars, 0.9433 x 1,000 = 943.3 944
- P(X<10) = 0.004893
- For P=0.99, X=? -> X=21.78 22
- For P=0.95, X=? -> X=20.15 21
Question 5:
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- Sample Size: n= p*q*(z/E)^2
n= 0.35*0.65*(1.96/0.02)^2
n= 498
Question 7:
(TCO D) Historically, 21% of professional tennis players use Wilson tennis balls. A randomly selected sample of 50 professional tennis players found that eight use Wilson tennis balls. Does the sample data provide evidence to conclude that the percentage of professional tennis players using Wilson tennis balls is less than 21% (with a = .10)? Use the hypothesis testing procedure, including the Hypotheses, all steps for both the p-value and rejection region approaches, and your Interpretation, using the variable and its units.
Answer:
The hypotheses include Ho: p >or=.21 and Ha: p<.21. For the given alpha=0.10, the critical value = -1.282, and the rejection region <or=-1.282. The test statistic z=-0.87 and the observed p-value=0.193. Because the test statistic is not in the Rejection region, and the p-value is not less that alpha, we cannot reject the null hypothesis that the population proportion is equal to or greater than .21, and we cannot accept the alternative hypothesis, that the population mean is less than .21, when the level of significance, alpha, is equal to .10. That is, we are less than 90% sure that less than 21% of professional tennis players use Wilson tennis balls.
Question 8:
(TCO D) A manufacturer of jogging shoes claims that the mean life of his product will exceed 50 hours. A random sample of 49 shoes leads to the following results in terms of useful life.
Sample Size = 49 shoes
Sample Mean = 58.3 hours
Sample Standard Deviation = 10.1 hours
Does the sample data provide evidence to conclude that the manufacturer’s claim is correct (using a = .02)? Use the hypothesis testing procedure, including the Hypotheses, all steps for both the p-value and rejection region approaches, and your Interpretation, using the variable and its units.
Answer:
The hypotheses include Ho : mu <or= 50, Ha: mu>50. For the given alpha=0.02, the critical value =2.054, and the rejection region >or= 2.054. The test statistic z=5.75 and the observed p-value=0.000. Because the test statistic is in the Rejection region, and the p-value is less that alpha, we can reject the null hypothesis, that the life of the jogging shoes is <or= 50 hours, and we can accept the alternative hypothesis, that the life of the jogging shoes is > 50 hours, at alpha = .02. That is, we are at least 98% sure that the average life of shoes exceeds 50 hours.
Question 9:
Use Minitab and the data below to run the Linear Regression, and use the Minitab output to answer the following questions. You can Copy and Paste the data set into Excel, and then Copy and Paste it into Minitab.
NOTE: ON THE FINAL EXAM YOU WILL BE PROVIDED THE MINITAB OUTPUT.
Suppose an appliance store conducts a 5-month experiment to determine the effect of advertising on sales revenue. Below is the output, including the scatterplot and regression output. Answer the questions below. (Data set: ADSALES)
| Advexp X ($100s) | Sales Y
($1000s) |
| 1 | 1 |
| 2 | 1 |
| 3 | 2 |
| 4 | 2 |
| 5 | 4 |
- Analyze the Minitab output to determine the regression equation.
b. Find and interpret ? ^ 1 hat in the context of this problem.
c. Find and interpret the coefficient of determination (r-squared).
d. Find and interpret the coefficient of correlation.
e. Does the data provide significant evidence (a = .05) that the advertising can be used to predict the sales? Test the utility of this model using a two-tailed test. Find the observed p-value and interpret.
f. Find the 95% confidence interval for the mean sales generated by $400 of advertising Interpret this interval.
g. Find the 95% prediction interval for the sales generated by $400 of advertising Interpret this interval. .
h. What can we say about the sales generated by $800 of advertising?
Answers:
- Y hat = -0.1 + 0.7 ADVEXP_X
- B1 hat = 0.7. Interpretation: Each $100 increase in Advertising results in an increase of $700 in Sales.
- R squared = 81.67%. Interpretation: The independent variable Advertising explains 81.67% of the variability in Sales.
- r = 0.9037. Interpretation: The correlation of 0.9037 indicates a strong positive relationship between Advertising and Sales.
- The null hypothesis Ho is that B1 = 0, and the alternative hypothesis Ha is that B1 is not equal 0. The p-value for the Advertising regression coefficient = 0.035. Interpretation: Because the p-value of 0.035 is less than the alpha = .05, we can reject the null hypothesis, that the regression coefficient = 0, and we can accept the alternative hypothesis, that the regression coefficient is not = 0. Yes, Advertising can be used to predict Sales in the population.
- The 95% confidence interval for the mean sales generated by $400 of Advertising is (1.64450, 3.75550). Interpretation: When the Advertising expenditure = $400, over numerous months, we can be 95% confident the mean Sales will be between $1,644.50 and $3,755.50).
- The 95% prediction interval for the sales generated by $400 of Advertising is (0.502806, 4.89719). Interpretation: When the Advertising expenditure = $400, in a particular month, we can be 95% confident the Sales will be between $502.81 and $4,897.19).
- Because $800 is outside the range of our Advertising variable, we cannot make a prediction about the Sales.
Question 10:
Use Minitab and the data below to run the Multiple Linear Regression, and use the Minitab output to answer the following questions. You can Copy and Paste the data set into Excel, and then Copy and Paste it into Minitab.
NOTE: ON THE FINAL EXAM YOU WILL BE PROVIDED THE MINITAB OUTPUT.
AGE NUM- PRICE
BIDS
127 13 1235
115 12 1080
127 7 845
150 9 1522
156 6 1047
182 11 1979
156 12 1822
132 10 1253
137 9 1297
113 9 946
137 15 1713
117 11 1024
137 8 1147
153 6 1092
117 13 1152
126 10 1336
170 14 2131
182 8 1550
162 11 1884
184 10 2041
143 6 845
159 9 1483
108 14 1055
175 8 1545
108 6 729
179 9 1792
111 15 1175
187 8 1593
111 7 785
115
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