At the Wilmington Trust Bank, on average 8 customers arrive per hour at the drive-through window. What is the probability that, in any hour, less than 8 will arrive Round your answer to 4 decimals.Question 1
\nAt the Wilmington Trust Bank, on average 8 customers arrive per hour at the drive-through window. What is the probability that, in any hour, less than 8 will arrive Round your answer to 4 decimals.<\/p>\n
0.4530<\/p>\n
0.4457<\/p>\n
0.4335<\/p>\n
0.4318<\/p>\n
5 points<\/p>\n
Question 2
\nUse this table for the following question.<\/p>\n
Supplier
\nNumber Conforming
\nNumber Nonconforming
\nA
\n101
\n3
\nB
\n95
\n6
\nC
\n36
\n2<\/p>\n
What is the probability of that a randomly selected part will be from supplier B, or a nonconforming unit from supplier A, or a conforming part from supplier C <\/p>\n
0.6846<\/p>\n
0.6620<\/p>\n
0.5761<\/p>\n
0.4854
\n5 points<\/p>\n
Question 3
\nThe number of cell phone minutes used by high school seniors during the school year follows a normal distribution with a mean of 625 and a standard deviation of 55. What is the probability that a student uses more than 575 minutes <\/p>\n
0.6475<\/p>\n
0.8133<\/p>\n
0.8186<\/p>\n
0.8925
\n5 points<\/p>\n
Question 4
\nOn the basis of past experience, 26% of the bills of a large mail-order book company are incorrect. If a random sample of seven current bills is selected what is the probability that two or less are incorrect <\/p>\n
0.6475<\/p>\n
0.7354<\/p>\n
0.9730<\/p>\n
0.9920
\n5 points<\/p>\n
Question 5
\nFord Motor Company is confident that its 2016 F-150 truck gets 26 miles per gallon on the highway. Before they begin to advertise this fact they want to be 98% certain of their claim. To accomplish this, they take a random sample of 250 trucks and measure their gas mileage. The average was 24.91 mpg with a population standard deviation of 4.77 mpg. Calculate the Upper and Lower Confidence Interval values AND can Ford make the claim that their trucks will get 26 mpg on the highway.<\/p>\n
Lower = 25.06, Upper = 26.94 & Claim is yes their trucks do get 26 mpg<\/p>\n
Lower = 24.38, Upper = 25.58 & Claim is no their trucks do not get 26 mpg<\/p>\n
Lower = 24.21, Upper = 25.61, & Claim is no their trucks do not get 26 mpg<\/p>\n
Lower = 24.19, Upper = 25.71, & Claim is no their trucks do not get 26 mpg
\n5 points<\/p>\n
Question 6
\nThe time required to complete a project is normally distributed with a mean of 110 weeks and a standard deviation of 13.65 weeks. The construction company must pay a penalty if the project is not finished by the due date in the contract. If a construction company bidding on this contract wishes to be 90 percent sure of finishing by the due date, what due date (project week #) should be negotiated <\/p>\n
112.39<\/p>\n
120.96<\/p>\n
124.08<\/p>\n
127.49
\n5 points<\/p>\n
Question 7
\nCustomers arrive at a supermarket checkout counter with an average arrival rate of 9 customers per hour. What is the probability of less than 7 customers arriving at the supermarket checkout counter in a given one-hour period <\/p>\n
0.2068<\/p>\n
0.1432<\/p>\n
0.0998<\/p>\n
0.0625
\n5 points<\/p>\n
Question 8
\nA local commuter bus service advertises that buses run every eighteen minutes along a certain route. What is the probability of a bus picking up the passengers at a given bus stop in less than or equal to 15 minutes following their arrival at the bus stop (Hint: Use the exponential distribution method to solve this question)<\/p>\n
0.5709<\/p>\n
0.5654<\/p>\n
0.5831<\/p>\n
0.5925
\n5 points<\/p>\n
Question 9
\nIf the average number of cars that passed through a toll both between 2:00 AM & 3:00 AM is sixteen, what is the probability that tonight exactly 19 cars would pass during the same time frame <\/p>\n
0.0418<\/p>\n
0.0467<\/p>\n
0.0699<\/p>\n
0.0814
\n5 points<\/p>\n
Question 10
\nIf on average the customer service center receives 24 calls per hour during the hours of noon till 3:00 PM. What is the probability that today 20 or more calls will be received <\/p>\n
0.8197<\/p>\n
0.8252<\/p>\n
0.8310<\/p>\n
0.8564
\n5 points<\/p>\n
Question 11
\nThe total expenses of a hospital are related to many factors. Two of these factors are the number of beds in the hospital, and the number of admissions. Data was collected on 8 hospitals as shown in the table below. Develop a regression model to predict the total expenses of a hospital based upon the number of beds.<\/p>\n
Expenses
\n# Beds
\n1
\n61
\n220
\n2
\n131
\n341
\n3
\n161
\n525
\n4
\n28
\n140
\n5
\n18
\n40
\n6
\n97
\n215
\n7
\n49
\n145
\n8
\n10
\n95<\/p>\n
Y = 0.339x \u2013 3.516<\/p>\n
Y = -15.64 \u2013 1.02x<\/p>\n
Y = 0.339x \u2013 2.128<\/p>\n
Y = .339x \u2013 5.822
\n5 points<\/p>\n
Question 12
\nThe total expenses of a hospital are related to many factors. Two of these factors are the number of beds in the hospital, and the number of admissions. Data was collected on 8 hospitals as shown in the table below. Develop a regression model to predict the total expenses of a hospital based upon the number of admissions.<\/p>\n
Expenses
\nAdmissions
\n1
\n61
\n81
\n2
\n131
\n164
\n3
\n161
\n230
\n4
\n28
\n47
\n5
\n18
\n13
\n6
\n97
\n159
\n7
\n49
\n57
\n8
\n10
\n7<\/p>\n
Y = 0.671x + 9.284<\/p>\n
Y = 5.426 + 0.675x<\/p>\n
Y = 0.671x + 3.931<\/p>\n
Y = .032x + 6.751
\n5 points<\/p>\n
Question 13
\nThe total expenses of a hospital are related to many factors. Two of these factors are the number of beds in the hospital, and the number of admissions. Data was collected on 8 hospitals as shown in the table below. Develop a regression model to predict the total expenses of a hospital based upon the number of beds and the number of admissions.<\/p>\n
Expenses
\n# Beds
\nAdmissions
\n1
\n61
\n220
\n81
\n2
\n131
\n341
\n164
\n3
\n161
\n525
\n230
\n4
\n28
\n140
\n47
\n5
\n18
\n40
\n13
\n6
\n97
\n215
\n159
\n7
\n49
\n145
\n57
\n8
\n10
\n95
\n7<\/p>\n
Y = 0.073X1 + 0.541X2 + 5.66<\/p>\n
Y = 0.073X1 +0.541X2 + 0.593<\/p>\n
Y = 1.02X1 -15.64X2 + 0.07<\/p>\n
Y = 0.079X1 +0.533X2 + 1.85
\n5 points<\/p>\n
Question 14
\nRefer to the data and your solutions to questions 11 \u2013 13 and identify which of the three models best predicts the expenses of a hospital.<\/p>\n
The regression model based upon beds only is the best because it has the highest r value.<\/p>\n
The regression model based upon admissions only is the best because it has the highest r value.<\/p>\n
The regression model based upon beds and admissions is the best because it has the highest r value.<\/p>\n
The regression model based upon beds only is the best because it has the highest r2 value.<\/p>\n
The regression model based upon admissions only is the best because it has the highest r2 value.
\n5 points<\/p>\n
Question 15
\nQuestion 13 states: \u201cThe total expenses of a hospital are related to many factors. Two of these factors are the number of beds in the hospital, and the number of admissions.\u201d Identify the F critical value for the regression model in Question 13.<\/p>\n
6.608<\/p>\n
5.786<\/p>\n
5.318<\/p>\n
4.459
\n5 points<\/p>\n
Question 16
\nThe owner of a bicycle repair and sales business has hired you to help him make his business more profitable. The following table shows sales data for one product for each month for the year (assume 30 days\/month). These data will be referenced in order to answer questions 16 \u2013 20.<\/p>\n
Month
\nSales
\nForecast
\nMonth 1
\n92
\n91
\nMonth 2
\n77<\/p>\n
Month 3
\n66<\/p>\n
Month 4
\n74<\/p>\n
Month 5
\n68<\/p>\n
Month 6
\n84<\/p>\n
Month 7
\n84<\/p>\n
Month 8
\n74<\/p>\n
Month 9
\n75<\/p>\n
Month 10
\n63<\/p>\n
Month 11
\n86<\/p>\n
Month 12
\n84<\/p>\n
Month 13<\/p>\n
Question 16: Use a 4-month moving average to calculate the sales forecast for months 5, 10 & 13.<\/p>\n
77.25, 79.25 & 77.00<\/p>\n
77.50, 79.75 & 76.75<\/p>\n
78.75, 81.00 & 78.25<\/p>\n
81.97, 79.28 & 79.38
\n5 points<\/p>\n
Question 17
\nRefer to the data in the Question 16 and use exponential smoothing at an alpha of 0.30 to calculate each month\u2019s forecast. What are the forecasts for Months 4, 10 & 12<\/p>\n
74.5, 75.75 & 77.5<\/p>\n
80.92, 77.74 & 76.82<\/p>\n
80.71, 77.16 & 76.84<\/p>\n
81.97, 79.28 & 79.38
\n5 points<\/p>\n
Question 18
\nRefer to the data in the Question 16 and calculate the seasonal index for Months 3 and 6.<\/p>\n
0.85 & 1.08<\/p>\n
0.85 & 1.09<\/p>\n
0.85 & 1.02<\/p>\n
0.83 & 1.06
\n5 points<\/p>\n
Question 19
\nRefer to the data in the Question 16 and use the forecast generated by the exponential smoothing method calculate the MAD for the data.<\/p>\n
9.29<\/p>\n
8.86<\/p>\n
8.19<\/p>\n
4.62
\n5 points<\/p>\n
Question 20
\nRefer to the data in the Question 16 and calculate the Weighted Average Forecast for Months 5 \u2013 13 where the most recent month carries a weight of 4, the next most recent month a weight of 3, the next a weight of 2 and finally the oldest month carries a weight of 1. The weights are arranged from the most recent month to the oldest month: 4, 3, 2, & 1. What are the forecasts for months 6, 9 & 13 <\/p>\n
71.2, 79.4 & 79.2<\/p>\n
73.7, 81.9 & 81.0<\/p>\n
75.2, 91.9 & 81.0<\/p>\n
70.3, 78.4 & 79.5<\/p>\n","protected":false},"excerpt":{"rendered":"
At the Wilmington Trust Bank, on average 8 customers arrive per hour at the drive-through window. What is the probability that, in any hour, less than 8 will arrive Round your answer to 4 decimals.Question 1 At the Wilmington Trust Read More …<\/a><\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[],"tags":[],"class_list":["post-93460","post","type-post","status-publish","format-standard","hentry"],"_links":{"self":[{"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/posts\/93460","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/comments?post=93460"}],"version-history":[{"count":0,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/posts\/93460\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/media?parent=93460"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/categories?post=93460"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/tags?post=93460"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}