{"id":77364,"date":"2018-02-20T23:50:30","date_gmt":"2018-02-20T23:50:30","guid":{"rendered":"https:\/\/writemyessayfree.com\/university-of-texas-phy-57880-final-exam-2014"},"modified":"2017-08-18T07:13:53","modified_gmt":"2017-08-18T07:13:53","slug":"university-of-texas-phy-57880-final-exam-2014","status":"publish","type":"post","link":"https:\/\/www.benedictsol.com\/blogs\/university-of-texas-phy-57880-final-exam-2014\/","title":{"rendered":"University of Texas PHY 57880 Final Exam 2014"},"content":{"rendered":"<h1>University of Texas PHY 57880 Final Exam 2014<\/h1>\n<p>PHYS 211 \u2013 Final Exam Spring 2014 Sample 2 Solutions<\/p>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image001.gif\" alt=\"\"><\/p>\n<p>1) A waiter is in an elevator, holding a stack of dishes. As observed by someone standing still on the ground floor, watching the elevator move down towards them with <em>constant<\/em>speed, what is the sign of the work done<em> by<\/em>the uppermost dish<em> on<\/em>the onedirectly below it?<\/p>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image003.jpg\" alt=\"\"><\/p>\n<p>2) The figure below shows the relation between position x and time t for a particle. Which of the following statements are true?<\/p>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image005.jpg\" alt=\"\"><\/p>\n<ol>\n<li>The particle\u2019s velocity is negative at a.<\/li>\n<\/ol>\n<ol>\n<li>The particle\u2019s acceleration is zero at a.<\/li>\n<\/ol>\n<ol>\n<li>The particle\u2019s acceleration is negative at f.<\/li>\n<\/ol>\n<ol>\n<li>The particle\u2019s velocity is negative at b.<\/li>\n<\/ol>\n<ol>\n<li>The particle\u2019s acceleration is roughly zero at c.<\/li>\n<\/ol>\n<ol>\n<li>The particle\u2019s velocity is zero at c.<\/li>\n<\/ol>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image006.gif\" alt=\"\"><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image007.gif\" alt=\"\"><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image008.gif\" alt=\"\"><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image009.gif\" alt=\"\"><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image010.gif\" alt=\"\"><\/p>\n<ol>\n<li>1, 2, 6<\/li>\n<\/ol>\n<ol>\n<li>3, 4, 5<\/li>\n<\/ol>\n<ol>\n<li>4, 6<\/li>\n<\/ol>\n<ol>\n<li>2, 3, 4<\/li>\n<\/ol>\n<ol>\n<li>2, 5<\/li>\n<\/ol>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image012.jpg\" alt=\"\"><\/p>\n<p>&nbsp;<\/p>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image013.gif\" alt=\"\">PHYS 211 \u2013 Final Exam Sample 2 Solutions<\/p>\n<p>3) A particle is in simple harmonic motion with period T. At time t = 0 it is halfway between the equilibrium point and an end point of its motion, traveling toward the end point. The next time it is at the same place is:<\/p>\n<p>A. t = T<\/p>\n<p>B. t = T\/2<\/p>\n<p>C. t = T\/4<\/p>\n<p>D. t = T\/8<\/p>\n<p><sub>4)<\/sub>A performer, seated on a trapeze, is swinging back and forth with a period of 8 s. If she stands up, thus raising the center of mass of the performer + trapeze system by 48 cm, what will be the new period of the trapeze? (Treat the system as a simple pendulum.)<\/p>\n<p>A. 8.00 s<\/p>\n<p>B. 11.5 s<\/p>\n<p>C. 7.88 s<\/p>\n<p>D. 5.01 s<\/p>\n<p>E. 8.12 s<\/p>\n<p>5) A bomber flying in level flight with constant velocity releases a bomb before it is over the target. Neglecting air resistance, which one of the following is NOT true?<\/p>\n<p>A. The bomber is over the target when the bomb strikes.<\/p>\n<p>B. The acceleration of the bomb is constant<\/p>\n<p>C. The horizontal velocity of the plane equals the vertical velocity of the bomb when it hits the target<\/p>\n<p>D. The bomb travels in a curved path.<\/p>\n<p>E. The time of flight of the bomb is independent of the horizontal speed of the plane.<\/p>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image014.gif\" alt=\"\"><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image015.gif\" alt=\"\"><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image017.jpg\" alt=\"\"><\/p>\n<p>&nbsp;<\/p>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image013.gif\" alt=\"\">PHYS 211 \u2013 Final Exam Sample 2 Solutions<\/p>\n<p>6) A man, holding a weight in each hand, stands at the center of a horizontal frictionless rotating turntable. The effect of the weights is to double the rotational inertia of the system. As he is rotating, the man opens his hands and drops the two weights. They fall outside the turntable.<\/p>\n<p>Then:<\/p>\n<ol>\n<li>his angular velocity doubles.<\/li>\n<\/ol>\n<ol>\n<li>his angular velocity remains about the same.<\/li>\n<\/ol>\n<ol>\n<li>his angular velocity is halved.<\/li>\n<\/ol>\n<ol>\n<li>the direction of his angular momentum vector changes.<\/li>\n<\/ol>\n<ol>\n<li>his rotational kinetic energy increases.<\/li>\n<\/ol>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image012.jpg\" alt=\"\"><\/p>\n<p>7) A block attached to a spring oscillates in simple harmonic motion along the x axis. The limits of its motion are x = 10 cm and x = 50 cm and it goes from one of these extremes to the other in 0.25 s. Its amplitude and frequency are:<\/p>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image018.gif\" alt=\"\"><\/p>\n<table>\n<tbody>\n<tr>\n<td><\/td>\n<td>A. 40 cm, 2 Hz<\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>B. 20 cm, 4 Hz<\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>C. 60 cm, 2 Hz<\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>D. 25 cm, 4 Hz<\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>E. 20 cm, 2 Hz<\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>8) A ball is released from rest on a no-slip surface,<\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>as shown in the figure. After reaching its lowest<\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>point, the ball begins to rise again, this time on a<\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>frictionless surface as shown in the figure. When the<\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>ball reaches its maximum height on the frictionless<\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>surface, it is<\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>A. at a greater height as when it was released.<\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>B. at a lesser height as when it was released.<\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>C. at the same height as when it was released.<\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>D. It is impossible to tell without knowing the<\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>mass of the ball.<\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>E. It is impossible to tell without knowing the<\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>radius of the ball.<\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image019.gif\" alt=\"\"><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image021.jpg\" alt=\"\"><\/p>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image013.gif\" alt=\"\">PHYS 211 \u2013 Final Exam Sample 2 Solutions<\/p>\n<p>9) An object on the end of a spring is set into oscillation by giving it an initial velocity while it is at its equilibrium position. In the first trial the initial velocity <em>v<\/em>is0 and in the second it is 4<em>v<\/em>0. In the second trial:<\/p>\n<p>A. the amplitude is half as great and the maximum acceleration is twice as great.<\/p>\n<p>B. the amplitude is twice as great and the maximum acceleration is half as great.<\/p>\n<p>C. both the amplitude and the maximum acceleration are twice as great.<\/p>\n<p>D. both the amplitude and the maximum acceleration are four times as great.<\/p>\n<p>E. the amplitude is four times as great and the maximum acceleration is twice as great.<\/p>\n<p>10) Consider a cylindrical toy which can switch from having its mass roughly equally distributed across its cross-section (solid cylinder) to having its mass concentrated at its outer edge (hollow cylinder). With the toy spinning on frictionless bearings around its central symmetry axis, you push a button and it converts from \u201csolid\u201d to \u201chollow\u201d mode.<\/p>\n<p>What happens to its rotational kinetic energy?<\/p>\n<ol>\n<li>Increases by a factor of 4<\/li>\n<\/ol>\n<ol>\n<li>Increases by a factor of 2<\/li>\n<\/ol>\n<ol>\n<li>Stays the same<\/li>\n<\/ol>\n<ol>\n<li>Decreases by a factor of 2<\/li>\n<\/ol>\n<ol>\n<li>Decreases by a factor of 4<\/li>\n<\/ol>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image012.jpg\" alt=\"\"><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image022.gif\" alt=\"\"><\/p>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image013.gif\" alt=\"\">PHYS 211 \u2013 Final Exam Sample 2 Solutions<\/p>\n<p>11) Consider this mobile in static equilibrium. The mobile is made with three masses, several massless cords, and two rod of negligible mass. If the mass labeled C is M, what is the <strong><em>mass of<\/em><\/strong> <strong><em>B<\/em><\/strong>?<\/p>\n<p>A. M\/6<\/p>\n<p>B. M\/2<\/p>\n<p>C. M\/3<\/p>\n<p>D. M<\/p>\n<p>E. 4M\/3<\/p>\n<p>12) A simple pendulum has length L and period T. As it passes through its equilibrium position, the string is suddenly clamped at its midpoint. The period then becomes:<\/p>\n<p>A. 2T<\/p>\n<p>B. T<\/p>\n<p>C. T\/2<\/p>\n<p>D. T\/4<\/p>\n<p>E. none of these<\/p>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image012.jpg\" alt=\"\"><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image023.gif\" alt=\"\"><\/p>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image013.gif\" alt=\"\">PHYS 211 \u2013 Final Exam Sample 2 Solutions<\/p>\n<p>13) Two particles, each of mass <em>m<\/em>, are a distance <em>d<\/em> apart. To bring a third particle, with mass 2<em>m<\/em>, from far away to a resting point midway between the two particles, the work done by an external agent is given by:<\/p>\n<p>A. 4<em>Gm<\/em><em><sup>2<\/sup><\/em><em>\/d<\/em><\/p>\n<p>B. -4<em>Gm<\/em><em><sup>2<\/sup><\/em><em>\/d<\/em><\/p>\n<p>C. 8<em>Gm<\/em><em><sup>2<\/sup><\/em><em>\/d<\/em><\/p>\n<p>D. -8<em>Gm<\/em><em><sup>2<\/sup><\/em><em>\/d<\/em><\/p>\n<p>E. 0<\/p>\n<p>&nbsp;<\/p>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image013.gif\" alt=\"\">PHYS 211 \u2013 Final Exam Sample 2 Solutions<\/p>\n<p>14) The velocity of an object is given by the expression <em>v<\/em>(<em>t<\/em>) = 3.00 m\/s + (4.00 m\/s<sup>3<\/sup>)<em>t<\/em><sup>2<\/sup>. Determine the position of the object as a function of time if it is located at <em>x<\/em> = 1.00 m at time <em>t<\/em> = 0.000 s.<\/p>\n<table>\n<tbody>\n<tr>\n<td><\/td>\n<td><\/td>\n<td><em>t<\/em><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>A.<\/td>\n<td>(4.00 m\/s)<em>t +<\/em> 1.00 m<\/td>\n<td><sub>s<\/sub>3<\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>B.<\/td>\n<td>(3.00 m\/s)<em>t<\/em> + (1.33 m\/s<sup>3<\/sup>)<em>t<\/em><em><sup>3<\/sup><\/em><\/td>\n<td><\/td>\n<td><\/td>\n<td>m<\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><em>C.<\/em><\/td>\n<td>(4.00 m\/s)<em>t<\/em><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>D. 1.33 m<\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image024.jpg\" alt=\"\"><\/p>\n<p>E. 1.00 m + (3.00 m\/s)<em>t<\/em> + (1.33 m\/s<sup>3<\/sup>)<em>t<\/em><sup>3<\/sup><\/p>\n<p>15) A 4.0 kg brick slides on a frictionless floor at 2.0 m\/s in the positive y-direction. A sticky piece of putty with a mass of 1.0 kg slides at 6.0 m\/s in the negative x-direction. The two collide and stick together. What is the speed of the brick-putty mass after the<\/p>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image026.jpg\" alt=\"\"><\/p>\n<p>&nbsp;<\/p>\n<p>collision?<\/p>\n<ol>\n<li>0.4 m\/s<\/li>\n<\/ol>\n<ol>\n<li>2.0 m\/s<\/li>\n<\/ol>\n<ol>\n<li>2.8 m\/s<\/li>\n<\/ol>\n<ol>\n<li>10 m\/s<\/li>\n<\/ol>\n<ol>\n<li>None of the above<\/li>\n<\/ol>\n<p>&nbsp;<\/p>\n<table>\n<tbody>\n<tr>\n<td>of linear momentum: (don\u2019t forget 2D<em>v<\/em><\/td>\n<td><\/td>\n<td><\/td>\n<td>=<\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><em>f<\/em><\/td>\n<td><em>f<\/em><\/td>\n<td><\/td>\n<td><\/td>\n<td><em>f<\/em><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td>s<\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td>s<\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>&nbsp;<\/p>\n<p>16)Two uniform circular wire loops of radius R and mass M are attached as shown. What is the 10.Sec07\/23<\/p>\n<p>moment of inertia of this object around an axis perpendicular to the page and through the point<\/p>\n<p>O? Note: The moment of inertia of a single ring around an axis through the center and<\/p>\n<p>perpendicular to the ring is MR<sup>2<\/sup>.<\/p>\n<p>A. MR2<\/p>\n<p>B. 2MR2<\/p>\n<p>C. 4MR2<\/p>\n<p>D. 8MR2<\/p>\n<p>E. 16MR2<\/p>\n<p>&nbsp;<\/p>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image013.gif\" alt=\"\">PHYS 211 \u2013 Final Exam Sample 2 Solutions<\/p>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image028.jpg\" alt=\"\"><\/p>\n<p>17) A pulley with radius <em>R<\/em> and moment of inertia <em>I<\/em> is free to rotate around a horizontal fixed axis through its center. A string passing over the pulley is attached to m<sub>1<\/sub> on one end and m<sub>2<\/sub> on the other. You observe m<sub>1<\/sub> is moving downward with speed v. If the string does not slip on the pulley, what is the approximate magnitude of the total angular momentum of the masses and pulley, taken around the pulley axis?<\/p>\n<ol>\n<li>|(m<sub>1<\/sub> \u2013 m<sub>2<\/sub>)vR + Iv\/R|<\/li>\n<li>|(m<sub>1<\/sub> + m<sub>2<\/sub>)vR + Iv\/R|<\/li>\n<li>|(m<sub>1<\/sub> \u2013 m<sub>2<\/sub>)vR \u2013 Iv\/R|<\/li>\n<\/ol>\n<ol>\n<li>|(m<sub>1<\/sub> + m<sub>2<\/sub>)vR \u2013 Iv\/R|<\/li>\n<\/ol>\n<ol>\n<li>none of the above<\/li>\n<\/ol>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image030.jpg\" alt=\"\"><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image031.gif\" alt=\"\"><\/p>\n<p>18)The length of a bicycle pedal arm is 12cm, and a downward force of 170 N is applied to the 10.Sec09\/10pedal by the rider\u2019s foot. What is the magnitude of the torque about the pedal arm\u2019s pivot point<\/p>\n<p>when the arm makes a 65\u00ba angle with the vertical?<\/p>\n<p>A. 20.4 Nm<\/p>\n<p>B. 8.62 Nm<\/p>\n<p>C. 4.20 Nm<\/p>\n<p>D. 18.5 Nm<\/p>\n<p>E. 5.05 Nm<\/p>\n<p>&nbsp;<\/p>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image013.gif\" alt=\"\">PHYS 211 \u2013 Final Exam Sample 2 Solutions<\/p>\n<p>19)The mass of planet Nittany is 3 times that of Earth and its radius is one half that of Earth. A toad13.Sec04\/4 weighing 300 N on Earth will <strong><em>weigh how much<\/em><\/strong> on Nittany?<\/p>\n<p>A. 3600 N<\/p>\n<p>B. 1800 N<\/p>\n<p>C. 400 N<\/p>\n<p>D. 225 N<\/p>\n<p>E. 25 N<\/p>\n<p>&nbsp;<\/p>\n<p>20) A heavy ball of putty (mass m=0.50 kg, speed v<sub>0<\/sub>=10 m\/s) is thrown at a block of wood (mass M=1.0 kg) which hangs at rest from a cord. The putty sticks to the wood. In the figure, snapshots show the system just before the putty hits, and later, when the putty\/block system has just come to a halt at the high point of its swing.<\/p>\n<p>&nbsp;<\/p>\n<p>Bef ore<\/p>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image033.jpg\" alt=\"\"><\/p>\n<table>\n<tbody>\n<tr>\n<td>v0<\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>m<\/td>\n<td>M<\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image035.gif\" alt=\"\"><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image037.gif\" alt=\"\"><\/p>\n<p>After<\/p>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image039.jpg\" alt=\"\"><\/p>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image041.jpg\" alt=\"\"><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image043.jpg\" alt=\"\"><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image045.jpg\" alt=\"\"> h m+M<img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image047.jpg\" alt=\"\"><\/p>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image049.jpg\" alt=\"\"><\/p>\n<p>&nbsp;<\/p>\n<p>In the \u201cafter\u201d picture, the center of mass of the whole system has risen a height \u201ch\u201d.<\/p>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image051.jpg\" alt=\"\"><\/p>\n<p>&nbsp;<\/p>\n<p>What is h? (Use g = 10 m\/s<sup>2<\/sup>)<\/p>\n<ol>\n<li>0.56 m<\/li>\n<\/ol>\n<ol>\n<li>1.7 m<\/li>\n<li>2.5 m<\/li>\n<li>5.0 m<\/li>\n<li>10. m<\/li>\n<\/ol>\n<p>&nbsp;<\/p>\n<table>\n<tbody>\n<tr>\n<td>9<\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>&nbsp;<\/p>\n<table>\n<tbody>\n<tr>\n<td>PHYS 211 \u2013 Final Exam<\/td>\n<td>Sample 2<\/td>\n<td>Solutions<\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>21) A hand pushes <em>horizontally<\/em> with a constant force on a physics book,<\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>holding it up against a wall. Nothing is moving.<\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td>m<sub>s<\/sub><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>The coefficient of static friction between the wall and book ism<sub>s.<\/sub><\/td>\n<td><\/td>\n<td><strong>F<\/strong>(hand)<\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>However, <em>there i<strong>s zero<\/strong><\/em> <em>static friction between the hand and the book<\/em>.<\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image053.jpg\" alt=\"\"><\/p>\n<p>If the hand suddenly increases its horizontal push to TWICE what it was before, what happens to the frictional force of the wall on the book?<\/p>\n<ol>\n<li>It doubles<\/li>\n<li>It increases by more than a factor of 2<\/li>\n<li>It increases, but by less than a factor of 2.<\/li>\n<li>It decreases.<\/li>\n<\/ol>\n<ol>\n<li>It stays exactly the same<\/li>\n<\/ol>\n<p>22) A cart is moving with a constant horizontal velocity of 5 m\/s. A small pebble (of negligible mass) is launched from the front of the cart with a velocity of10<img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image055.jpg\" alt=\"\"><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image057.jpg\" alt=\"\">3m\/s at 60.0\u00b0 above the horizontal as measured relative to the cart (see figure) and experiences no significant air resistance. Using the approximation that g = 10 m\/s<sup>2<\/sup>, just as the pebble returns to the level from which it was launched, its distance from the front of the cart is closest to<\/p>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image059.jpg\" alt=\"\"><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image061.jpg\" alt=\"\"><\/p>\n<p>&nbsp;<\/p>\n<p>A) 15(<img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image063.jpg\" alt=\"\"><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image065.jpg\" alt=\"\">3-1) m.<\/p>\n<p>B) 15(<img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image067.jpg\" alt=\"\"><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image065.jpg\" alt=\"\">3+1)m.<\/p>\n<p>C) 10<img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image055.jpg\" alt=\"\"><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image057.jpg\" alt=\"\">3m.<\/p>\n<p>D) 15<img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image055.jpg\" alt=\"\"><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image057.jpg\" alt=\"\">3m.<\/p>\n<p>E) 20<img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image055.jpg\" alt=\"\"><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image057.jpg\" alt=\"\">3m.<\/p>\n<p>&nbsp;<\/p>\n<p>10<img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image069.jpg\" alt=\"\"><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image071.jpg\" alt=\"\">3m\/s<\/p>\n<p>5 m\/s<\/p>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image073.jpg\" alt=\"\"><\/p>\n<table>\n<tbody>\n<tr>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td>s<sup>2<\/sup><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>&nbsp;<\/p>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image013.gif\" alt=\"\">PHYS 211 \u2013 Final Exam Sample 2 Solutions<\/p>\n<p>23) If we neglect the Earth\u2019s atmosphere and any rotational effects, with what initial minimum speed would we have to fire a projectile vertically in order for it never to fall back down? The Earth<\/p>\n<p>has mass ME = 6\u00d710<sup>24<\/sup> kg and is a sphere of radius RE = 6.4 \u00d710<sup>6<\/sup> m. The projectile is an inert mass acted on by gravity alone, and is not a rocket.<\/p>\n<p>A. 11,200 m\/s<\/p>\n<p>B. 4,400 m\/s<\/p>\n<p>C. 22,200 m\/s<\/p>\n<p>D. 67,300 m\/s<\/p>\n<p>E. 123,400 m\/s<\/p>\n<p>&nbsp;<\/p>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image013.gif\" alt=\"\">PHYS 211 \u2013 Final Exam Sample 2 Solutions<\/p>\n<p>24) A mass moves on a frictionless plane. It is attached to a string (length <em>r<\/em>) and is swinging about the origin with constantly increasing angular velocity. At time t = 0 s it is<\/p>\n<table>\n<tbody>\n<tr>\n<td>moving with velocity<\/td>\n<td>\u02c6<\/td>\n<td>and has a linear acceleration pointing 45 degrees above the \u2013x<\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><em>v<\/em><strong>j<\/strong><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>\u02c6<\/td>\n<td>\u02c6<\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>axis in the(-<strong>i<\/strong><\/td>\n<td>+<strong> j<\/strong>)direction. From this point in time how long will you have to wait for its<\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<p>speed to double?<\/p>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image075.jpg\" alt=\"\"><\/p>\n<p>A. <em>r<\/em><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image077.jpg\" alt=\"\"><em>v<\/em><\/p>\n<p>B. 2<em>r<\/em><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image079.jpg\" alt=\"\"><em>v<\/em><\/p>\n<p>C. 2<em>p<\/em> <em>r<\/em> <img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image079.jpg\" alt=\"\"><em>v<\/em><\/p>\n<ol>\n<li>It is impossible to know with the given information<\/li>\n<\/ol>\n<ol>\n<li>None of the above<\/li>\n<\/ol>\n<p><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image080.gif\" alt=\"\"><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image081.gif\" alt=\"\"><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image082.gif\" alt=\"\"><img decoding=\"async\" src=\"\/Users\/HOMEWO~1\/AppData\/Local\/Temp\/msohtmlclip1\/01\/clip_image083.gif\" alt=\"\"><\/p>\n<p>25) A swimmer heads directly across a river 300 m wide. A person with a radar gun stands 400 m downstream on the opposite bank and sees the swimmer heading straight at them at 1 m\/s. How fast is the river flowing?<\/p>\n<p>A. 1 m\/s<\/p>\n<table>\n<tbody>\n<tr>\n<td>B. 0.8 m\/s<\/td>\n<td><\/td>\n<td>400 m<\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td>vriver<\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>C. 0.6 m\/s<\/td>\n<td>300 m<\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td>D. Not enough information to determine<\/td>\n<td>vstill water<\/td>\n<td>500 m<\/td>\n<td><\/td>\n<td><\/td>\n<\/tr>\n<tr>\n<td><\/td>\n<td>E. None of the above<\/td>\n<td>vwrt land<i><a href=\"http:\/\/essaysharkbestwriters.com\/\" target=\"_blank\">Click here to have a similar paper done for you by one of our writers within the set deadline at a discounted<\/a>\u2026<\/i><\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n","protected":false},"excerpt":{"rendered":"<p>University of Texas PHY 57880 Final Exam 2014 PHYS 211 \u2013 Final Exam Spring 2014 Sample 2 Solutions 1) A waiter is in an elevator, holding a stack of dishes. As observed by someone standing still on the ground floor, <a href=\"https:\/\/www.benedictsol.com\/blogs\/university-of-texas-phy-57880-final-exam-2014\/\" class=\"read-more\">Read More &#8230;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[],"tags":[],"class_list":["post-77364","post","type-post","status-publish","format-standard","hentry"],"_links":{"self":[{"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/posts\/77364","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/comments?post=77364"}],"version-history":[{"count":0,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/posts\/77364\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/media?parent=77364"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/categories?post=77364"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/tags?post=77364"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}