QuestionQuestion 1 (4 points) Question 1 Unsaved<\/p>\n
The __________ step to creating a COMPUTER solution is to analyze the problem.<\/p>\n
Question 1 options:<\/p>\n
third<\/p>\n
first<\/p>\n
second<\/p>\n
fourth<\/p>\n
Save<\/p>\n
Question 2 (4 points) Question 2 Unsaved<\/p>\n
Between the switch statement\ufffd\ufffd\ufffds opening and closing braces are the individual __________ clauses.<\/p>\n
Question 2 OPTIONS:<\/p>\n
if<\/p>\n
else<\/p>\n
case<\/p>\n
if\/else<\/p>\n
Save<\/p>\n
Question 3 (4 points) Question 3 Unsaved<\/p>\n
You can use a(n) __________ to help you desk-check an algorithm.<\/p>\n
Question 3 options:<\/p>\n
flowchart<\/p>\n
pseudocode<\/p>\n
IPO chart<\/p>\n
desk-check TABLE
\nSave<\/p>\n
Question 4 (4 points) Question 4 Unsaved<\/p>\n
If the default clause is not the last clause in the switch statement, you will need to include a __________ statement at the end of the clause to stop the computer from processing the instructions in the next case clause.<\/p>\n
Question 4 options:<\/p>\n
stop<\/p>\n
break<\/p>\n
continue<\/p>\n
switch<\/p>\n
Save<\/p>\n
Question 5 (4 points) Question 5 Unsaved<\/p>\n
The evaluation of the condition in a __________ loop occurs before the instructions within the loop are processed.<\/p>\n
Question 5 options:<\/p>\n
for<\/p>\n
pretest<\/p>\n
while<\/p>\n
posttest<\/p>\n
Save<\/p>\n
Question 6 (4 points) Question 6 Unsaved<\/p>\n
The do while statement must end with a(n) __________.<\/p>\n
Question 6 options:<\/p>\n
;<\/p>\n
.<\/p>\n
,<\/p>\n
\/\/end do while comment<\/p>\n
Save<\/p>\n
Question 7 (4 points) Question 7 Unsaved<\/p>\n
The __________ step to creating a COMPUTER solution is to code the algorithm into a program.<\/p>\n
Question 7 options:<\/p>\n
third<\/p>\n
second<\/p>\n
fourth<\/p>\n
fifth<\/p>\n
Save<\/p>\n
Question 8 (4 points) Question 8 Unsaved<\/p>\n
A program that displays a message based on a letter grade that the user enters would require a(n) __________ selection structure.<\/p>\n
Question 8 options:<\/p>\n
nested<\/p>\n
multiple-alternative<\/p>\n
if<\/p>\n
else<\/p>\n
Save<\/p>\n
Question 9 (4 points) Question 9 Unsaved<\/p>\n
The __________ condition tells the computer when to stop looping through the instructions.<\/p>\n
Question 9 options:<\/p>\n
repeat<\/p>\n
continue<\/p>\n
loop exit<\/p>\n
looping<\/p>\n
Save<\/p>\n
Question 10 (4 points) Question 10 Unsaved<\/p>\n
In the code shown below, the computer continues processing the inner loop\ufffd\ufffd\ufffds instructions until the user enters __________, at which time the inner loop ends.<\/p>\n
int sales = 0;<\/p>\n
int region = 1;<\/p>\n
int totRegSales = 0;<\/p>\n
while (region < 3)\n\n{\n\ncout << \"First sales amount for Region \"\n\n<< region << \": \";\n\ncin >> sales;<\/p>\n
while (sales > 0)<\/p>\n
{<\/p>\n
totRegSales = totRegSales + sales;<\/p>\n
cout << \"Next sales amount for Region \"\n\n<< region << \": \";\n\ncin >> sales;<\/p>\n
} \/\/end while<\/p>\n
cout << endl << \"Region \" << region << \" sales: $\"\n\n<< totRegSales << endl << endl;\n\nregion = region + 1;\n\ntotRegSales = 0;\n\n} \/\/end while\n\ncout << \"End of program\" << endl;\n\nQuestion 10 options:\n\na negative number\n\na number greater or equal than 3\n\nthe number 0\n\neither the number 0 or a negative number\n\nSave\n\nPrevious PageNext Page\n\nQuestion 11 (4 points)\n\n__________ means to assign a beginning value to a counter or accumulator variable.\n\nQuestion 11 options:\n\nFlushing\n\nIterating\n\nAccumulating\n\nInitializing\n\nSave\n\nQuestion 12 (4 points)\n\nThe __________ combines the object file with other machine code necessary for your C++ program to run correctly.\n\nQuestion 12 options:\n\ninterpreter\n\nassembler\n\nlinker\n\ncompiler\n\nSave\n\nQuestion 13 (4 points)\n\nThe linker produces a(n) __________ file, which is a file that contains all of the machine code necessary to run your C++ program as many times as desired without the need for translating the program again.\n\nQuestion 13 options:\n\nsource\n\nexecutable\n\nobject\n\ninclude\n\nSave\n\nQuestion 14 (4 points)\n\nIn the code shown below, the __________ clause begins the inner loop.\n\nint sales = 0;\n\nint region = 1;\n\nint totRegSales = 0;\n\nwhile (region < 3)\n\n{\n\ncout << \"First sales amount for Region \"\n\n<< region << \": \";\n\ncin >> sales;<\/p>\n
while (sales > 0)<\/p>\n
{<\/p>\n
totRegSales = totRegSales + sales;<\/p>\n
cout << \"Next sales amount for Region \"\n\n<< region << \": \";\n\ncin >> sales;<\/p>\n
} \/\/end while<\/p>\n
cout << endl << \"Region \" << region << \" sales: $\"\n\n<< totRegSales << endl << endl;\n\nregion = region + 1;\n\ntotRegSales = 0;\n\n} \/\/end while\n\ncout << \"End of program\" << endl;\n\nQuestion 14 options:\n\nint totRegSales = 0;\n\nwhile (region < 3)\n\ncin >> sales;<\/p>\n
while (sales > 0)<\/p>\n
Save<\/p>\n
Question 15 (4 points)<\/p>\n
An assignment statement __________ create(s) a variable in memory.<\/p>\n
Question 15 options:<\/p>\n
does not<\/p>\n
always<\/p>\n
may not<\/p>\n
may<\/p>\n
Save<\/p>\n
Question 16 (4 points)<\/p>\n
In a for clause, the __________ argument specifies the condition that must be true for the loop to continue processing the loop body instructions.<\/p>\n
Question 16 options:<\/p>\n
last<\/p>\n
first<\/p>\n
second<\/p>\n
third<\/p>\n
Save<\/p>\n
Question 17 (4 points)<\/p>\n
A __________ is a C++ instruction that causes the COMPUTER to perform some action after it is executed, or processed, by the computer.<\/p>\n
Question 17 options:<\/p>\n
directive<\/p>\n
processing item<\/p>\n
statement<\/p>\n
keyword<\/p>\n
Save<\/p>\n
Question 18 (4 points)<\/p>\n
Consider the following pseudocode:<\/p>\n
1. enter the code and sales amount<\/p>\n
2. calculate the bonus amount by multiplying the sales amount by .08<\/p>\n
3. if (the code is X)<\/p>\n
if (the sales are greater than or equal to 10000)<\/p>\n
add 150 to the bonus amount<\/p>\n
else<\/p>\n
add 125 to the bonus amount<\/p>\n
end if<\/p>\n
end if<\/p>\n
4. display the bonus amount<\/p>\n
If the code is X and the sales amount is 15000, the value of the bonus amount at the end of the algorithm in the accompanying figure will be __________.<\/p>\n
Question 18 options:<\/p>\n
1200<\/p>\n
845<\/p>\n
1350<\/p>\n
720<\/p>\n
Save<\/p>\n
Question 19 (4 points)<\/p>\n
Logical operators are sometimes referred to as __________ operators.<\/p>\n
Question 19 options:<\/p>\n
Relational<\/p>\n
Comparison<\/p>\n
Conditional<\/p>\n
Boolean<\/p>\n
Save<\/p>\n
Question 20 (4 points)<\/p>\n
The first of two DIAMONDS encountered along a path in a flowchart represents the condition of the __________ selection structure of a nested selection structure.<\/p>\n
Question 20 options:<\/p>\n
switch<\/p>\n
inner<\/p>\n
nested<\/p>\n
outer<\/p>\n
Save<\/p>\n
Previous PageNext PagePage 2 of 3<\/p>\n
________________________________________<\/p>\n
Question 21 (4 points)<\/p>\n
In a flowchart, the oval symbol is called the __________ symbol.<\/p>\n
Question 21 options:<\/p>\n
process<\/p>\n
selection<\/p>\n
start\/stop<\/p>\n
input\/output<\/p>\n
Save<\/p>\n
Question 22 (4 points)<\/p>\n
The And operator in C++ is __________.<\/p>\n
Question 22 options:<\/p>\n
!<\/p>\n
||<\/p>\n
&&<\/p>\n
&<\/p>\n
Save<\/p>\n
Question 23 (4 points)<\/p>\n
The selection structure is also called the __________ structure.<\/p>\n
Question 23 options:<\/p>\n
DIAMOND
\nswitch<\/p>\n
decision<\/p>\n
case<\/p>\n
Save<\/p>\n
Question 24 (4 points)<\/p>\n
__________ an algorithm refers to the process of translating the algorithm into a language that the COMPUTER can understand.<\/p>\n
Question 24 options:<\/p>\n
Assembling<\/p>\n
Translating<\/p>\n
Coding<\/p>\n
Tracing<\/p>\n
Save<\/p>\n
Question 25 (4 points)<\/p>\n
The processing portion of an IPO chart might include a __________.<\/p>\n
Question 25 options:<\/p>\n
statement about the input data<\/p>\n
statement about the output data<\/p>\n
notation to the user of the program<\/p>\n
flowchart<\/p>\n","protected":false},"excerpt":{"rendered":"
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