{"id":33808,"date":"2018-02-20T23:50:30","date_gmt":"2018-02-20T23:50:30","guid":{"rendered":"https:\/\/writemyessayfree.com\/abaqus-assignment-4-report-2"},"modified":"2017-08-16T06:21:27","modified_gmt":"2017-08-16T06:21:27","slug":"abaqus-assignment-4-report-2","status":"publish","type":"post","link":"https:\/\/www.benedictsol.com\/blogs\/abaqus-assignment-4-report-2\/","title":{"rendered":"Abaqus Assignment 4 Report"},"content":{"rendered":"<div class=\"the_content_wrapper\">\n<p> Introduction:<br \/> The objective of this report is to discuss the effects the linear and non-linear tension<br \/> has on the analytical model of a cube.<br \/> For the first problem, it was required to sketch a cube of specific dimensions. The<br \/> cube was assigned specific materials of young modulus of E=110 Mpa and Poisson<br \/> ratio of v=0.35<br \/> The cube was then assigned linear and non-linear tension modes and the results<br \/> compared for both cases.<br \/> Finite element results from Abaqus:<br \/> In fig.1, a contour plot of the displacement along the x-axis is present for both linear<br \/> and non-linear tension cubes.<br \/> Discussion:<br \/> In a linear element the displacement across the element is considered linear. In<br \/> other words, you can use simple interpolation between nodes to find the<br \/> displacement at any point on a linear element.<br \/> Non-linear here means that the curve load-displacement is no more proportional.<br \/> As seen in table 1 above:<br \/> \u2013 For Linear Geometry: The Nominal stain, nominal stress and force per nodes are <br \/> approximately equal in both cases for the abaqus and theoretical results.<br \/> \u2013 For Non-Linear Geometry: The true strain, strain along y-axis and true stress are <br \/> approximately equal in both cases for the abaqus and theoretical results.<br \/> \u2013 The nodal force for the non-linear geometry is non accurate when comparing the <br \/> abacus results and theoretical results.<br \/> Table 1, demonstrates the effect the NLGEOM mode has on an analytical model of a <br \/> cube under specific boundary conditions.<br \/> Furthermore, the two plots in fig4 &amp; fig5 further demonstrates the differences in results the <br \/> NLGEOM mode has on results. It also shows that for the geometric non linearity, the strain <br \/> varies as well as the displacement as the application of the load becomes non uniform.<br \/> Problem 2<br \/> Introduction:<br \/> In problem 2, a point load of 1.3933 mm was applied to the corner of a cube. For case 1, the <br \/> cube was meshed with element type C3D8, which is a full integration hexahedral element. <br \/> For the second case, Von -Mises results are compared for both cases.<br \/> Discussion:<br \/> The maximum stress with element type C3D8 is almost four times greater than the<br \/> maximum stress with element type C3D8<br \/> This highlights the important of choosing the right element type to mesh the design,<br \/> as it has a large impact on the Von-misses (deformation) results and analysis.<br \/> Hourglass term come into picture if you are using reduced integration elements.<br \/> Because of under integration you will get spurious modes, which needs to be<br \/> avoided as it produces meaningless results.<br \/> Due to the complexity of distribution of the point stress on the cube corner, the<br \/> design required an element type to be analysed accurately by using fully integrated<br \/> elements not reduced integration.<br \/> As seen in fig.6, there is almost an error in the formation representation given<br \/> assigning as an element type to the mesh.<br \/> The results above in fig.6 verify that Hourgalssing can be addressed by using fully<br \/> integrated elements.<br \/> Problem 3<br \/> Introduction:<br \/> In problem 3, the task is to highlight the differences and limitation between the element <br \/> choices on Abacus. The following three elements will be compared to the theoretical <br \/> results:<br \/> ? Reduced integration hexahedral (brick) element (C3D8R)<br \/> ? Full integration linear hexahedral (brick) element(C3D8)<br \/> ? Incompatible element (C3D8I)<br \/> A concentrated force will be applied with magnitude of 8000N to the vertices of a set of <br \/> point<br \/> The force will results in the downward bending of the beam and a step will be created for <br \/> analysis of at least 20 incriminations.<br \/> The results from the 3 simulations will be presented along with plots of the shape of the <br \/> deformed beam.<br \/> Lastly, there will be a brief discussion of results and comparisons with theoretical <br \/> calculation.<br \/> Discussion:<br \/> The reduced integration results for deflection compared to the theoretical calculation are <br \/> off by a margin of about 10 mm which is very inaccurate and proves that the reduced <br \/> integration is not accurate and a bad choice for trying to predict the bending response of a <br \/> beam.<br \/> On the other hand the full and incompatible integration seem to be quite accurate when <br \/> compared to the theoretical results in fig. and table. 2and fig.8 .This proves that full and <br \/> incompatible integration are both good choices for predicting the beams bending response <br \/> and deflection along the deformed beam.<br \/> However in fig.7, there is an inaccuracy in the stress values for the full integration elements. <br \/> Therefore, the incompatible integration would be more accurate in interpreting accurate <br \/> overall results for the deflection of the beam. As it couses enhancements to the <br \/> deformation gradients which allow a first-order element to have a linear variation of the <br \/> deformation gradient across the element\u2019s domain.<br \/> To conclude, element choices have proven to have a missive impact on the results obtained <br \/> form abacus. Choosing the right element type is crucial when analysis a design on abacus, as <br \/> the integrity of the results might be effected and impact greatly on the performance of the <br \/> designed model.<\/p>\n<\/div>\n","protected":false},"excerpt":{"rendered":"<p>Introduction: The objective of this report is to discuss the effects the linear and non-linear tension has on the analytical model of a cube. For the first problem, it was required to sketch a cube of specific dimensions. The cube <a href=\"https:\/\/www.benedictsol.com\/blogs\/abaqus-assignment-4-report-2\/\" class=\"read-more\">Read More &#8230;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[],"tags":[],"class_list":["post-33808","post","type-post","status-publish","format-standard","hentry"],"_links":{"self":[{"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/posts\/33808","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/comments?post=33808"}],"version-history":[{"count":0,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/posts\/33808\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/media?parent=33808"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/categories?post=33808"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/tags?post=33808"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}