Need help with these problems with steps ( due after 11 hours from now )1. Find the parametric equations for the following curves:<\/p>\n
A. The line segment from P = (9; 8; 5) to Q = (13;-2; 0).<\/p>\n
B. x^2 + y^2 = 9 for only positive x values.<\/p>\n
2. Find the vector valued function describing the curves of intersection of the pairs of surfaces. Then draw the two surfaces together in the space provided.<\/p>\n
A. The parabaloid y = x^2 + z^2 and the parabolic cylinder z = x^2.<\/p>\n
B. The cylinder x^2 + y^2 = 1 and the parabolic cylinder z = x^2.<\/p>\n
3. If a particle has an initial position of ~r(0) = i^ – 2j^ and its velocity is given by the vector function ~v(t) = < 2e^(2t) ; 3t^2- 1; t^3> , find the particles position function and acceleration function.<\/p>\n
4. Find the tangent line to the curve ~r(t) = < 3ln(t) , 2t -3 , 1\/t> at t= 1<\/p>\n
5. If a particle follows the path dened by ~r(t) = < 2t^(3\/2) ; 2t+1; sort(5)t > and starts at t = 0, at what time will the particle have traveled a total of 14 units?<\/p>\n
6. Let ~r(t) = < t; t; 2 -t^2>. Find the curvature when t = 0, denoted by K(0).<\/p>\n
7.write vector valued function for the paths from the north pole to south pole of the unit sphere below:<\/p>\n
A. along the intersection with the plane x=0 where y>= 0.<\/p>\n
B. along intersection with the plane y=x where x,y >= 0<\/p>\n
C. along a path that curves the sphere once counterclockwise as views in the xy-plane.<\/p>\n
9. r(t)= ( (1\/3)t^3, (1\/sqrt(2)), t )<\/p>\n
A. find the length t=1<\/p>\n
B. find the curvature when t=2<\/p>\n
c.find the unite tangent, unit normal and unit bi-normal vector for the function at the point where t=1<\/p>\n","protected":false},"excerpt":{"rendered":"
Need help with these problems with steps ( due after 11 hours from now )1. Find the parametric equations for the following curves: A. The line segment from P = (9; 8; 5) to Q = (13;-2; 0). B. x^2 Read More …<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[],"tags":[],"class_list":["post-231873","post","type-post","status-publish","format-standard","hentry"],"_links":{"self":[{"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/posts\/231873","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/comments?post=231873"}],"version-history":[{"count":0,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/posts\/231873\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/media?parent=231873"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/categories?post=231873"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/tags?post=231873"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}