{"id":203773,"date":"2018-09-14T04:21:53","date_gmt":"2018-09-14T04:21:53","guid":{"rendered":"http:\/\/localhost\/wordpress\/index.php\/2018\/09\/14\/bshs-382-week-3-quiz\/"},"modified":"2018-10-24T08:57:51","modified_gmt":"2018-10-24T08:57:51","slug":"bshs-382-week-3-quiz","status":"publish","type":"post","link":"https:\/\/www.benedictsol.com\/blogs\/bshs-382-week-3-quiz\/","title":{"rendered":"BSHS 382 Week 3 Quiz"},"content":{"rendered":"<p>1. \ufffd\u00a0\u00a0\u00a0 Follow the steps to compute the variance and standard deviation for the following population.\t\u00a0\t49\u00a0\u00a0\u00a0\u00a0 51\u00a0\u00a0\u00a0 53\u00a0\u00a0 55\u00a0\u00a0 57\u00a0\u00a0 59\u00a0 61\t\u00a0\t2. \ufffd\u00a0\u00a0\u00a0 For a sample of 289 female heights, the mean was 65.3 inches and the standard deviation was 2.8 inches. The shortest person in this sample had of 56 inches.\ta. \ufffd\u00a0\u00a0\u00a0 Find the z-score for the height of 56 inches.\tb. \ufffd\u00a0\u00a0\u00a0 What does the negative sign for the z-score represent?\tc. \ufffd\u00a0\u00a0\u00a0 Is this observation a potential outlier according to the three standard deviation distance criterion? Explain.\t\u00a0\t3. \ufffd\u00a0\u00a0\u00a0 A company decides to investigate the amount of sick leave taken by its employees. A sample of seven employees yields the following numbers of days of sick leave taken in the past year.\t\u00a0\t\u00a01 1 3 0 1 6 2\t\u00a0\tUse this information to answer parts a through c.\t\u00a0\t4. \ufffd\u00a0\u00a0\u00a0 What is the effect of the outlier?\t\u00a0\t5. \ufffd\u00a0\u00a0\u00a0 A survey asked 6189 random adults the question &#8220;How many children have you ever had?&#8221;\ufffd Use the results shown below to answer the following questions.\t\u00a0\t# no of children \ufffd \ufffd 0 \ufffd \ufffd \ufffd \ufffd 1 \ufffd \ufffd \ufffd 2 \ufffd \ufffd\u00a0\u00a0 3 \ufffd \ufffd\u00a0 4 \ufffd \ufffd\u00a0\u00a0 5 \ufffd \ufffd\u00a0\u00a0 6 \ufffd \ufffd\u00a0 7\tn \ufffd\u00a0\u00a0\u00a0\u00a0 1851 \ufffd \ufffd\u00a0\u00a0 869 \ufffd \ufffd 1462 \ufffd\u00a0 945 \ufffd 494 \ufffd\u00a0\u00a0\u00a0 281 \ufffd\u00a0\u00a0 153 \ufffd\u00a0 93\t\u00a0\ta. \ufffd\u00a0\u00a0\u00a0 Find the standard error of the sample mean of the random sample of 6189 adults.\tb. \ufffd\u00a0\u00a0\u00a0 Construct a 95% confidence interval for the population mean \u00b5.\tCan it be concluded that the population mean is less than 2.0?\tc. \ufffd\u00a0\u00a0\u00a0 On what assumptions is the analysis in part (b) based?\tIs the assumption of randomization valid?\tIs the assumption that the population distribution is approximately normal a valid assumption?\t\u00a0\t6. \ufffd\u00a0\u00a0\u00a0 A survey asked the question &#8220;What do you think is the ideal number of children for a family to have?&#8221;\ufffd The 473 females who responded had a median of 2, mean of 3.13, and standard deviation of 1.48. Answer parts a-d.\t\u00a0\ta. \ufffd\u00a0\u00a0\u00a0 What is the point estimate of the population mean?\tb. \ufffd\u00a0\u00a0\u00a0 Find the standard error of the sample mean.\tc. \ufffd\u00a0\u00a0\u00a0 The 95% confidence interval is (3,3.26). Interpret.\td. \ufffd\u00a0\u00a0\u00a0 Is it plausible that the population mean \u00b5 = 2?<\/p>\n","protected":false},"excerpt":{"rendered":"<p>1. \ufffd\u00a0\u00a0\u00a0 Follow the steps to compute the variance and standard deviation for the following population. \u00a0 49\u00a0\u00a0\u00a0\u00a0 51\u00a0\u00a0\u00a0 53\u00a0\u00a0 55\u00a0\u00a0 57\u00a0\u00a0 59\u00a0 61 \u00a0 2. \ufffd\u00a0\u00a0\u00a0 For a sample of 289 female heights, the mean was 65.3 inches and <a href=\"https:\/\/www.benedictsol.com\/blogs\/bshs-382-week-3-quiz\/\" class=\"read-more\">Read More &#8230;<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[],"tags":[],"class_list":["post-203773","post","type-post","status-publish","format-standard","hentry"],"_links":{"self":[{"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/posts\/203773","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/comments?post=203773"}],"version-history":[{"count":0,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/posts\/203773\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/media?parent=203773"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/categories?post=203773"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/tags?post=203773"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}