\nQUESTION 1
\n1.\tEvaluate the function at the indicated value of x. Round your result to three decimal places.
\nFunction: f(x) = 0.5x Value: x = 1.7<\/p>\n
\t-0.308<\/p>\n
\t1.7<\/p>\n
\t0.308<\/p>\n
\t0.5<\/p>\n
\t-1.7
\nQUESTION 2
\n1.\tMatch the graph with its exponential function.<\/p>\n
\n\ty = 2-x – 3<\/p>\n
\ty = -2x + 3<\/p>\n
\ty = 2x + 3<\/p>\n
\ty = 2x – 3<\/p>\n
\ty = -2x – 3<\/p>\n
QUESTION 3
\n1.\tSelect the graph of the function.
\nf(x) = 5x-1<\/p>\n
\nQUESTION 4
\n1.\tEvaluate the function at the indicated value of x. Round your result to three decimal places.
\nFunction: f(x) = 500e0.05x Value: x=17<\/p>\n
\t1169.823<\/p>\n
\t1369.823<\/p>\n
\t1569.823<\/p>\n
\t1269.823<\/p>\n
\t1469.823<\/p>\n
QUESTION 5
\n1.\tUse the One-to-One property to solve the equation for x.
\ne3x+5 = e6<\/p>\n
\tx = -1\/3<\/p>\n
\tx2 = 6<\/p>\n
\tx = -3<\/p>\n
\tx = 1\/3<\/p>\n
\tx = 3<\/p>\n
QUESTION 6
\n1.\tWrite the logarithmic equation in exponential form.
\nlog8 64 = 2<\/p>\n
\t648 = 2<\/p>\n
\t82 = 16<\/p>\n
\t82 = 88<\/p>\n
\t82 = 64<\/p>\n
\t864 = 2<\/p>\n
QUESTION 7
\n1.\tWrite the logarithmic equation in exponential form.
\nlog7 343 = 3<\/p>\n
\t7343 = 2<\/p>\n
\t73 = 77<\/p>\n
\t73 = 343<\/p>\n
\t73 = 14<\/p>\n
\t3437 = 2<\/p>\n
QUESTION 8
\n1.\tWrite the exponential equation in logarithmic form.
\n43 = 64<\/p>\n
\tlog64 4 = 3<\/p>\n
\tlog4 64 = 3<\/p>\n
\tlog4 64 = -3<\/p>\n
\tlog4 3 = 64<\/p>\n
\tlog4 64 = 1\/3<\/p>\n
QUESTION 9
\n1.\tUse the properties of logarithms to simplify the expression.
\nlog20 209<\/p>\n
\t0<\/p>\n
\t-1\/9<\/p>\n
\t1\/9<\/p>\n
\t-9<\/p>\n
\t9<\/p>\n
QUESTION 10
\n1.\tUse the One-to-One property to solve the equation for x.
\nlog2(x+4) = log2 20<\/p>\n
\t19<\/p>\n
\t17<\/p>\n
\t18<\/p>\n
\t16<\/p>\n
\t20<\/p>\n
QUESTION 11
\n1.\tFind the exact value of the logarithmic expression.
\nlog6 36<\/p>\n
\t2<\/p>\n
\t6<\/p>\n
\t36<\/p>\n
\t-2<\/p>\n
\tnone of these<\/p>\n
QUESTION 12
\n1.\tUse the properties of logarithms to expand the expression as a sum, difference, and\/or constant multiple of logarithms. (Assume all variables are positive.)
\nlog3 9x<\/p>\n
\tlog3 9 x log3 x<\/p>\n
\tlog3 9 + log3 x<\/p>\n
\tlog3 9 log3<\/p>\n
\tnone of these<\/p>\n
QUESTION 13
\n1.\tCondense the expression to a logarithm of a single quantity.
\nlogx – 2logy + 3logz<\/p>\n
\nQUESTION 14
\n1.\tEvaluate the logarithm using the change-of-base formula. Round your result to three decimal places.
\nlog4 9<\/p>\n
\t1.585<\/p>\n
\t5.585<\/p>\n
\t3.585<\/p>\n
\t4.585<\/p>\n
\t2.585
\nQUESTION 15
\n1.\tDetermine whether the given x-value is a solution (or an approximate solution) of the equation.
\n42x-7 = 16
\nx = 5<\/p>\n
\tno<\/p>\n
\tyes
\nQUESTION 16
\n1.\tSolve for x.
\n3x = 81<\/p>\n
\t7<\/p>\n
\t3<\/p>\n
\t4<\/p>\n
\t-4<\/p>\n
\t-3
\nQUESTION 17
\n1.\tSolve the exponential equation algebraically. Approximate the resulte to three decimal places.
\ne5x = ex2-14<\/p>\n
\t-7, -2<\/p>\n
\t7, -2<\/p>\n
\t5, -14<\/p>\n
\t7, 2<\/p>\n
\t-7, 2
\nQUESTION 18
\n1.\tSolve the logarithmic equation algebraically. Approximate the result to three decimal places.
\nlog3(6x-8) = log3(5x + 10)<\/p>\n
\t18<\/p>\n
\t20<\/p>\n
\t17<\/p>\n
\t19<\/p>\n
\t-2
\nQUESTION 19
\n1.\tFind the magnitude R of each earthquake of intensity I (let I0=1).
\nI = 19000<\/p>\n
\t3.28<\/p>\n
\t5.28<\/p>\n
\t4.28<\/p>\n
\t2.38<\/p>\n
\t6.28
\nQUESTION 20
\n1.\t$2500 is invested in an account at interest rate r, compounded continuously. Find the time required for the amount to double. (Approximate the result to two decimal places.)
\nr = 0.0570<\/p>\n
\t13.16 years<\/p>\n
\t10.16 years<\/p>\n
\t11.16 years<\/p>\n
\t12.16 years<\/p>\n
\t14.16 years<\/p>\n
<\/p>\n","protected":false},"excerpt":{"rendered":"
QUESTION 1 1. Evaluate the function at the indicated value of x. Round your result to three decimal places. Function: f(x) = 0.5x Value: x = 1.7 -0.308 1.7 0.308 0.5 -1.7 QUESTION 2 1. Match the graph with its Read More …<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"closed","ping_status":"closed","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[],"tags":[],"class_list":["post-1988","post","type-post","status-publish","format-standard","hentry"],"_links":{"self":[{"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/posts\/1988","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/comments?post=1988"}],"version-history":[{"count":0,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/posts\/1988\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/media?parent=1988"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/categories?post=1988"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/tags?post=1988"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}