Algebra QuizQuestion 1<\/p>\n
Select the correct description of right-hand and left-hand behavior of the graph of the polynomial function.
\u0192(x) = 4\u00d72 \u2013 5x + 4
Falls to the left, rises to the right.
Falls to the left, falls to the right.
Rises to the left, rises to the right.
Rises to the left, falls to the right.
Falls to the left.<\/p>\n
5 points
Question 2<\/p>\n
Describe the right-hand and the left-hand behavior of the graph of
t(x) = 4\u00d75 \u2013 7\u00d73 \u2013 13
Because the degree is odd and the leading coefficient is positive, the graph falls to the left and rises to the right.
Because the degree is odd and the leading coefficient is positive, the graph rises to the left and rises to the right.
Because the degree is odd and the leading coefficient is positive, the graph falls to the left and falls to the right.
Because the degree is odd and the leading coefficient is positive, the graph rises to the left and falls to the right.
Because the degree is even and the leading coefficient is positive, the graph rises to the left and rises to the right.<\/p>\n
5 points
Question 3<\/p>\n
Select the correct description of right-hand and left-hand behavior of the graph of the polynomial function.
\u0192(x) = 3 \u2013 5x + 3\u00d72 \u2013 5\u00d73
Falls to the left, rises to the right.
Falls to the left, falls to the right.
Rises to the left, rises to the right.
Rises to the left, falls to the right.
Falls to the left.<\/p>\n
5 points
Question 4<\/p>\n
Select from the following which is the polynomial function that has the given zeroes.
2,-6
f(x) = x2 \u2013 4x + 12
f(x) = x2 + 4x + 12
f(x) = -x2 -4x \u2013 12
f(x) = -x2 + 4x \u2013 12
f(x) = x2 + 4x \u2013 12<\/p>\n
5 points
Question 5<\/p>\n
Select from the following which is the polynomial function that has the given zeroes.
0,-2,-4
f(x) = -x3 + 6\u00d72 + 8x
f(x) = x3 \u2013 6\u00d72 + 8x
f(x) = x3 + 6\u00d72 + 8x
f(x) = x3 \u2013 6\u00d72 \u2013 8x
f(x) = x3 + 6\u00d72 \u2013 8x<\/p>\n
5 points
Question 6<\/p>\n
Sketch the graph of the function by finding the zeroes of the polynomial.
f(x) = 2\u00d73 \u2013 10\u00d72 + 12x
0,2,3
https:\/\/content.grantham.edu\/at\/MA105\/exams\/w5_6_a.jpg
0,2,-3
https:\/\/content.grantham.edu\/at\/MA105\/exams\/w5_6_b.jpg
0,-2,3
https:\/\/content.grantham.edu\/at\/MA105\/exams\/w5_6_c.jpg
0,2,3
https:\/\/content.grantham.edu\/at\/MA105\/exams\/w5_6_d.jpg
0,-2,-3
https:\/\/content.grantham.edu\/at\/MA105\/exams\/w5_6_e.jpg<\/p>\n
5 points
Question 7<\/p>\n
Select the graph of the function and determine the zeroes of the polynomial.
f(x) = x2(x-6)
0,6,-6
https:\/\/content.grantham.edu\/at\/MA105\/exams\/w5_7_a.jpg
0,6
https:\/\/content.grantham.edu\/at\/MA105\/exams\/w5_7_b.jpg
0,-6
https:\/\/content.grantham.edu\/at\/MA105\/exams\/w5_7_c.jpg
0,6
https:\/\/content.grantham.edu\/at\/MA105\/exams\/w5_7_d.jpg
0,-6
https:\/\/content.grantham.edu\/at\/MA105\/exams\/w5_7_e.jpg<\/p>\n
5 points
Question 8<\/p>\n
Use the Remainder Theorem and Synthetic Division to find the function value.
g(x) = 3\u00d76 + 3\u00d74 \u2013 3\u00d72 + 6, g(0)
6
3
-3
8
7<\/p>\n
5 points
Question 9<\/p>\n
Use the Remainder Theorem and Synthetic Division to find the function value.
f(x) = 3\u00d73 \u2013 7x + 3, f(5)
-343
343
345
340
344<\/p>\n
5 points
Question 10<\/p>\n
Use the Remainder Theorem and Synthetic Division to find the function value.
h(x) = x3 \u2013 4\u00d72 \u2013 9x + 7, h(4)
-28
-27
-31
-25
-29<\/p>\n
5 points
Question 11<\/p>\n
Use synthetic division to divide:
(3\u00d73 \u2013 24\u00d72 + 45x \u2013 54) \u00f7 (x-6)
6\u00d72 \u2013 3x \u2013 9, x ? 6
6\u00d72 -3x \u2013 9, x ? 6
3\u00d72 \u2013 6x + 9, x ? 6
3\u00d72 \u2013 6x \u2013 9, x ? 6
3\u00d72 + 6x + 9, x ? 6<\/p>\n
5 points
Question 12<\/p>\n
Use synthetic division to divide:
(x3 \u2013 27x + 54) \u00f7 (x \u2013 3)
x2 + 3x \u2013 18, x ? 3
x2 \u2013 3x \u2013 27, x ? 3
x2 + 9x + 18, x ? 3
x2 + 9x \u2013 6, x ? 3
x2 + 6x + 9, x ? 3<\/p>\n
5 points
Question 13<\/p>\n
Use synthetic division to divide:
(4\u00d73 \u2013 9x + 16\u00d72 \u2013 36) \u00f7 (x + 4)
4\u00d72 \u2013 9, x ? -4
4\u00d72 + 9, x ? -4
-4\u00d72 \u2013 9, x ? -4
4\u00d73 \u2013 9, x ? -4
4\u00d73 + 9, x ? -4<\/p>\n
5 points
Question 14<\/p>\n
Use synthetic division to divide:
https:\/\/content.grantham.edu\/at\/MA105\/exams\/w5_14.jpg
5\u00d72 + 45x + 25, x ? 1\/5
16\u00d72 + 80x + 20, x ? 1\/5
100\u00d72 + 45x + 400, x ? 1\/5
20\u00d72 + 180x + 400, x ? 1\/5
4\u00d72 + 21x + 20, x ? 1\/5<\/p>\n
5 points
Question 15<\/p>\n
Find all of the zeroes of the function.
(x \u2013 3)(x + 9)3
-3,9
3,9
-3,-9
-3,3,9
3,-9<\/p>\n
5 points
Question 16<\/p>\n
Find all the rational zeroes of the function.
x3 \u2013 12\u00d72 + 41x \u2013 42
-2, -3, -7
2, 3, 7
2, -3, 7
-2, 3, 7
-2, 3, -7<\/p>\n
5 points
Question 17<\/p>\n
Determine all real zeroes of f.
f(x) = x3 + x2 \u2013 25x \u2013 25
-5,1,0
5,0,-5
-5,-1,5
-5,0,0
5,-1,0<\/p>\n
5 points
Question 18<\/p>\n
The height, h(x), of a punted rugby ball is given by https:\/\/content.grantham.edu\/at\/MA105\/exams\/w5_18.jpg where x is the horizontal distance in feet from the point where the ball is punted. How far, horizontally, is the ball from the kicker when it is at its highest point?
28 feet
13 feet
18 feet
23 feet
16 feet<\/p>\n
5 points
Question 19<\/p>\n
The profit P (in hundreds of dollars) that a company makes depends on the amount x (in hundreds of dollars) the company spends on advertising according to the model.
P(x) = 230 + 40x \u2013 0.5\u00d72
What expenditure for advertising will yield a maximum profit?
40
0.5
230
20
115<\/p>\n
5 points
Question 20<\/p>\n
The total revenue R earned per day (in dollars) from a pet-sitting service is given by
R(p) = -10p2 + 130p
where p is the price charged per pet (in dollars).
Find the price that will yield a maximum revenue.
$7.5
$6.5
$8.5
$9.5
$10.5<\/p>\n","protected":false},"excerpt":{"rendered":"
Algebra QuizQuestion 1 Select the correct description of right-hand and left-hand behavior of the graph of the polynomial function. \u0192(x) = 4\u00d72 \u2013 5x + 4 Falls to the left, rises to the right. Falls to the left, falls to Read More …<\/a><\/p>\n","protected":false},"author":1,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[],"tags":[],"class_list":["post-187941","post","type-post","status-publish","format-standard","hentry"],"_links":{"self":[{"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/posts\/187941","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/users\/1"}],"replies":[{"embeddable":true,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/comments?post=187941"}],"version-history":[{"count":0,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/posts\/187941\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/media?parent=187941"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/categories?post=187941"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.benedictsol.com\/blogs\/wp-json\/wp\/v2\/tags?post=187941"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}